Recent content by PhysicsOPhun

Thanks to everyone who offered their help today... I've spent a week reading a physics book and have been very into it. I'm just doing it for myself so that I could help my friends and family with it if need be. It's a lot harder than I expected but hopefully with some help myself I'll be able...

very very very simple question...for you So if v = d\sqrt{k/m} how can i turn that into solving for "k"? Homework Equations The Attempt at a Solution

thank you tiny tim...i remember. Really, if there's something that's troubling me...it's very hard for me to get out of the cycle, like my brain shuts down. If I had the answer, and the other values which I don't know...i could work backwards and make perfect sense of it all...

I'm not irritated, I've already gone through that stage...I'm just in my "got to have the answer" so I can figure out what had to be done to get it. I don't know what the velocity was at the moment of maximum compression. I don't know how to calculate to get those values. I have...

I have trouble rearranging the variables to solve for the one I need. Also, I don't understand what mv^2common is... What will this equation look like with my numbers plugged in. I want to work at backwards, understand it conceptually...

{mv^2_{common} - Would this be the value 2/v = .60m/s ? and in terms of mass, do I just double the mass of each box? Oh, and Sourbah...putting up my work would not help, it's most definatley wrong. I just basically guessed...not much learning there.

I set the change of potential energy equal to the change in kinetic energy. Then I took final velocity .6m/s and subtracted initial velocity 1.2m/s and set the product of that to equal force constant times the amount the spring collapsed. Having all those values, I calculated for "k". ...?

Hi, I Need to know exactly how to solve this...I just can't take it anymore. The only reason I'm so into it now is because I don't get it. I promised my girlfriend I would help her and now she's annoyed because I get more into it than she does. But anyway, someone..PLEASE tell me what has to be...

I Really hope someone is up and dying to do some physics problems! Hi guys, I'm the original poster... I'm pretty much just staring at the problem and have been for quite some time...Can someone private message me or e-mail or reply here and help me out with some details...I'm going in...

Sillybean... Hey Sillybean, you have a message! :redface:

I'm sorry...I just don't follow. If block 2 moves slower (stopped) then block 1, block 1 will push block 2 so that the springs (restorative force?...is that like potential energy?). The way I'm brainstorming it is that say, without the springs the block would have to be moving at a velocity...

Can someone clarify this please? Confusing Wording... 1.Two blocks, each with a mass 0.40 {\rm kg}, can slide without friction on a horizontal surface. Initially, block 1 is in motion with a speed v = 1.2 {\rm m/s}; block 2 is at rest. When block 1 collides with block 2, a spring bumper on...

Two blocks, each with a mass 0.40 {\rm kg}, can slide without friction on a horizontal surface. Initially, block 1 is in motion with a speed v = 1.2 {\rm m/s}; block 2 is at rest. When block 1 collides with block 2, a spring bumper on block 1 is compressed. Maximum compression of the spring...

Springs, Kinetic Friction, and Distance...help me please 1. In the figure below a 1.4 {\rm kg} block is held at rest against a spring with a force constant k = 740 {\rm N/m}. Initially, the spring is compressed a distance d. When the block is released, it slides across a surface that is...