Recent content by pmalayavech

ok thanks,

Homework Statement Hi, I am answering Question #3, and using the formula and variables above scratch area as reference on how to answer the question. Could someone please have a look and see if the problem I worked out came out correct. Homework Equations The Attempt at a Solution First I...

Homework Statement To increase the temperature of 50 grams of water by 2 Celsius degrees requires? Homework Equations The Attempt at a Solution As I understand it takes one caloric to increase 1 gram of water to 1 *C..Correct? since its 50 grams raised by 2*C, I have 50x2= 100 calories?

so its not in Joules? but Celsius?

Homework Statement Need a second person to help verify if answer is correct. Copper with a mass of 300 g initially at 200 °C is added to water with an initial temperature of 10 °C and mass of 500 g. What is the final temperature of the system when they are in equilibrium? ANSWER must be in...

Thank you, I understand now. after working out the problem, it was common sense to have to have it at 20cm, to evenly distribute the weight. 8000cc=8000cw, duhh And yes the "net" force is adding it all up i presume 130 Joules I was able to turn this in complete now, even though late, its...

still trying, and no references to check answers with

Just the last one for #2, this is my first time working on this type of problem. how should I combine the other 2 pulleys? value correct? 10N x radius #2 of 1m= 10Nm and the other T1=15N x radius#1 of 2m= 60Nm?? do i have atleast these values correct?

need help with the second one. please

#1, for Tcc= -8000gcm the fact that fulcrum only moved to the left 10cm (at 40cm), where it ought to be balance at 50cm (center), if we had 2 equal weights on both side, it would balance "cc" at 0cm and "cw" at 100cm, agree? so, since fulcrum moved to the left 10cm(40cm), weight at 0cm, on...

Alright, for #1 for Larm 1 I did r(1)=0-40 =-40cm Tcc= -40 x 200 =-800 gcm for m1La2 now for m2LA2 i am stuck

i) yes, same diagram ii) ok, no equations, I was thinking about conservation, where net force will equal to zero. ok, cc is negative and cw is positive? -40Nm-15Nm+60Nm= 15Nm from the pulley, I am looking at the left side as negatives and the right side positives. I hope I had multiplied the...

Tim!, hey thanks that is correct, so it would be (20N)(2m)+(15N)(1M)cc=(30N)(2m)cw (45Joules)cc = (60Joules)cw there for the net force is a Fnet of 15 Joules counterclockwise YES, i need help on the first one as well, any idea, please.

THANKS, I ONLY NEED HELP #2 NOW, PLEASE 10/31/12 @ 9:10 pm bumpHomework Statement 1)If the fulcrum of a 0.1 kg meter stick was placed at the 40 cm mark and a 200 g mass at the 0 cm mark, would it be possible to balance the meter stick with a 200 g mass on the long side of the meter stick? What...