Verify Final Temperature of Cu-Water System?

AI Thread Summary
The discussion revolves around calculating the final temperature of a copper-water system in thermal equilibrium. The initial conditions include 300 g of copper at 200 °C and 500 g of water at 10 °C. The user attempts to solve the problem using the heat transfer equation but mistakenly questions the units of the final temperature, initially thinking it should be in Joules. Clarification is provided that the final temperature is indeed measured in degrees Celsius, not Joules. Emphasizing the importance of consistent units throughout calculations is recommended to avoid confusion.
pmalayavech
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Homework Statement



Need a second person to help verify if answer is correct.

Copper with a mass of 300 g initially at 200 °C is added to water with an initial temperature of 10 °C and mass of 500 g. What is the final temperature of the system when they are in equilibrium?

ANSWER must be in JOULES

My variables

Cu specific heat: 385.112 J/kg C

Water specificheat: 4186 J

Homework Equations



Mm Cm (Tm - Tf) = Mw Cw (Tf-Tw)

The Attempt at a Solution



Mm Cm (Tm - Tf) = Mw Cw (Tf-Tw)

I convert g to kg for mass
500g to .500kg and 300g to .300kgnow plug equation and work the algebraic equation

(.300) (385.112)(200-tf) = (.500)(4186)(tf-10)

to

(23106.72-115.5336Tf)=(2093Tf-20930)

to

4036.72 = 2208.5336 Tf

to

19.93934799 = Tf

Tf= 19.9 J/kg C
 
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Get the same answer but units oC.
 


so its not in Joules? but Celsius?
 


pmalayavech said:
so its not in Joules? but Celsius?
Yes, the answer is a temperature, so it cannot be in Joules.
It is a good idea to include the units in the equations all the way through. This helps in two ways. It can show up dimensional mismatches (like Joules versus degrees) and also aids in conversion between different units of the same dimension (oC v. oF).
 
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