Recent content by posion117

thanks ^^

so if the Ψ(x)=(2/a)^(1/2) {csin(πx/a)+dsin(2πx/a)} do the <P>=0 ??

Ψ(x)=(2/a)^(1/2) [csin(nπx/a)] The Expectation value of momentum <P>=∫Ψ＊(x)[-ih d/dx ] Ψ(x) dx = 0 the average momentum is zero.It means the particle is moving equally in the +x and -x. And if Ψ(x)=(2/a)^(1/2) {csin(πx/a)+dsin(2πx/a)} I calculate the average momentum is also...