Homework Statement
A sheet of charge, ρs = -25 x 10^-25 C/m^2, intersects the x-axis @ x = 2, the y-axis @ y = 3, and the z-axis @ z = 4. Additionally a point charge of Q = 12.5 x 10^-6 C is located @ (-5, 2, 3). Find the resultant electric field due to the sheet and the point charge @ (-5...
it would work that way too, but i just don't know what to do, as the professor specifically asked for it to be done "by series". and i am at a loss as to knowing how it can be done that way.
yeah, i just simplified it on my homework, but after that, would you simply just plug 0 into x? it may give 0 for this problem, but for the other problems (after find the power series for them) it wouldn't give the right answer... so what would i do?
Homework Statement
My calc teacher says that we should do the problem "by series", even though it is in the section of the book where the teach L'Hopital's rule.
For example, one of the questions is:
\lim_{x\rightarrow 0} \frac{sin(x)}{\sqrt{x}}
The Attempt...
Homework Statement
A certain amount of a monatomic ideal gas undergoes the process shown in the figure below, in which its pressure doubles and its volume triples.
In terms of the number of moles, n, the initial pressure, Pi, and the initial volume, Vi, determine the quantities...
I am sorry to bring this up from 2 years ago (lol...), but I am having trouble on this exact problem. I can't find a way to combine the two equations to get the final and initial energies. Any help would be greatly appreciated.
Yes, with no additional weight to the spring would be zero displacement. When more weight was hung, we measured the length of the spring and subtracted the original additional-weightless length for the displacement.
I'll see if I can make one
EDIT: Here we go. What we did was measure the initial length of th spring like this, then added a weight, measured the length of the spring, and subtracted initial from the new length for the dsiplacement.
well, we took the initial measurement of the string from while it was hanging to eliminate weight as a force acting on the spring (since it would be constant). I'm confused by what you mean with unstretched length because we weren't required to take that measurement.
Well, I thought it was due to the the weight of the spring, but my teacher said that that was wrong. I have no clue why it wouldn't be zero any other way.