I noticed that. But I can't derive it out if I use different indices...
I don't know how to turn
g^{\mu \sigma}g_{\lambda \rho}(\nabla_\sigma \nabla^\rho \nabla _\mu K^\lambda)
into
\nabla _\lambda \nabla^\mu \nabla_\mu K^\lambda
Hi~
R_{\mu \lambda} \nabla ^\mu K^\lambda =0
is due to the Killing Equation and the symmetry of Ricci tensor R_{\mu \lambda} = R_{\lambda \mu}
But it seems like
\nabla ^\mu \nabla _\sigma \nabla _\mu K^\sigma \neq \nabla _\sigma \nabla ^\mu \nabla _\mu K^\sigma ??
Thanks for Reply!
Homework Statement
I'm currently self-studying Carroll's GR book and get stuck by proving
the following identity:
K^\lambda \nabla _\lambda R = 0
where K is Killing vector and R is the Ricci ScalarHomework Equations
Mr.Carroll said that it is suffice to show this by knowing:
\nabla _\mu...
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