Recent content by PSN03

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    Relationship between Cp, Cv and R

    Thanks a lot for your help. I was beating my head about this problem for long but finally it's done. Good day and stay safe 😊
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    Relationship between Cp, Cv and R

    Thanks a lot for your help. By the way only that much information is provided. can I conclude that Cp/n is molar heat capacity and Cp/M is specific heat capacity and Cp is just heat capacity, right?
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    Relationship between Cp, Cv and R

    According to me a=b cause what I have been learning is R is gas constant and hence it will be same for both. But the solution have says something else. According to them Cp-Cv=R/M where M is the molecular mass of gas. So is the above mentioned formula correct? Do we have to take that M term...
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    Position of the object and image in this optics problem

    Thanks a lot. I got my mistake. Good day and thanks for your time.
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    Position of the object and image in this optics problem

    That will happen when pin is at F
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    Position of the object and image in this optics problem

    I know the point you are telling me is take the rays after passing through lens. These ray will strike the mirror perpendicularly. These perpendicular rays will come back to the lens and hence give the object at same place. But won't this image formed by upright and not inverted? Also what is...
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    Position of the object and image in this optics problem

    What I thought was first take just the lens. Let this lens form an image at say B. This B will act as object for the mirror. The reflection of B comes back to A. This was my thinking.
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    Position of the object and image in this optics problem

    I know how to solve the problem but the only thing that's bothering me is what is A? According to me A is should be 2F ie 2 times the focal length distance. I thought of it like this: 1. First there will be an image formed due to the lens. 2. The image will be formed below the lens but the...
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    Forces at the bottom of a rotating U-tube filled with water

    I think I understood what my mistake was. Thanks for your help and time, means a lot to me😊
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    Forces at the bottom of a rotating U-tube filled with water

    I am not getting the point that why aren't they taking atmospheric pressure into consideration with the centrifugal force.
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    Forces at the bottom of a rotating U-tube filled with water

    Yes, initially there is no rotation so the water in only in the horizontal tube with x=0 Once the rotation starts we find some water in the vertical tube as well with its length as x. The two diagrams also say so.
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    Forces at the bottom of a rotating U-tube filled with water

    It should be zero as no rotation is happening. The initial condition is same.
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    Forces at the bottom of a rotating U-tube filled with water

    But according to the solution that I have, they haven't considered the atmospheric pressure in the left part while equating the forces, so is the solution provided wrong? And yes d is density, r=distance of centre of mass from point of rotation=l+x/2 Therefore Mω²r=d*A*(l-x)*ω²*(l+x)/2 (Sorry...
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