Recent content by puck

Ahh, that makes perfect sense now! I thought I had the angle wrong, as it was a rather small angle [and the range and max height were not the same]. Thanks! -Steve

Is the answer 63.43 degrees? I used these equations: vox*t = voy*t - .5gt^2 vf = voy + at with a = -g [due to gravity being negative] vf = voy - gt 0 = voy - gt since final velocity at peak height is zero t = voy/g Then subsitute: 2(vox*voy/g) = 2(voy^2/g) - g*(voy^2/g^2)...

Hey, I'm having a problem determining the angle necessary for the range of a projectile to equal the max height given the velocity of the projectile. (the velocity is 53.1m/s) I'd imagine it's necessary to set the equation for max height equal to the range? Either way, I'm dumbfounded on...