Hi,
##(1)## is verified by ##x_n=L## when ##n## is even and ##x_n=L+n## when ##n## is odd (indeed, for ##\epsilon>0## and ##n_0##, define ##n=2n_0## which satisfies the condition) but this sequence is clearly unbounded.
##(3)## leads to ##x_n=L, \forall n \geqslant n_0## (indeed, take given...