Homework Statement
The plug for the drain of a water tower is located 3.0 m below the surface. The plug is circular and has a diameter of 5.0 cm. If the density of water is 1000 kg/m3 , how much force is required to remove the plug (you may ignore the weight of the plug itself)
Homework...
Okay so I would calculate :
area of me = 0.5 b * h
area of grandma = 0.5 bh + lw ( split the curve into triangle and rectangle )
would i then : area of me - area of grandma ?
Homework Statement
Homework Equations
The Attempt at a Solution
I honestly have no clue as to how to go about this question. Am i supposed to find the area under the curve? but how do i do that without y axis numbers. am i supposed to look at the slopes?
Homework Statement
Homework Equations
The Attempt at a Solution
I knew the answer was between A and B, but the inward curves and outward curves on the position time graph confused me , what exactly does it mean?
-does A have an increasing velocity and then B has a decreasing velocity? im...
Homework Statement
A motorist drives north for 35.9min at 73.3km/hr and then stops for 15.4min. He then continues north, traveling 114.5km in 1.93hr. What is his average velocity?
Homework Equations
avg velocity = xf - xi / time
The Attempt at a Solution
35.9 min * (1 hr / 60 min) = 0.5983...
okay i now understand that I got the normal force equation wrong it is:
Fn = mg -T sin 45
why is the tension force negative? isn't Ty in the upward positive direction?
In the question, they stated the kinetic friction as 0.5 , which is what uk is.
and frictional force, ff, is uk * normal force (fn), therefore Ff = uk * Fn ? right?
I made the second equation as you said:
Fy=sin 45 T -mg+ Fn =0
solved for T and got -0.9998
i must be doing something wrong...
Homework Statement
Homework Equations
The Attempt at a Solution
Here is what i have done so far:
Fx = cos 45 T - Ff =ma
Fy=sin 45 T -mg+ Fn =ma
I found ff= uk * Fn = 0.5 *sin 45 +mg
fn = sin 45 +mg
Isolated for T in the x and y:
Tx = ma + Ff / cos 45 = 13.404
Ty = ma +mg - Fn / sin 45...
oh man... i totally messed up there, thank you so much for the correction! m2 will then = 9012
(10012 kg)(0 m/s) =m1v1 + m2v2
0= (1000 kg)(112 m/s)+ (9012 kg) (v2)
v2 = -12.43 m/s
Homework Statement
The mass of a spaceship is 10012 kg. The spaceship is at rest. Then one part of the ship with a mass of 1000 kg is ejected and emerges with a speed of 112 m/s. What is the speed of the other part?
Homework Equations
The Attempt at a Solution
I tried:
pi=pf
mivi=mfv2...