Recent content by qwertyqwert321

Homework Statement The plug for the drain of a water tower is located 3.0 m below the surface. The plug is circular and has a diameter of 5.0 cm. If the density of water is 1000 kg/m3 , how much force is required to remove the plug (you may ignore the weight of the plug itself) Homework...

Okay so I would calculate : area of me = 0.5 b * h area of grandma = 0.5 bh + lw ( split the curve into triangle and rectangle ) would i then : area of me - area of grandma ?

Homework Statement Homework EquationsThe Attempt at a Solution I honestly have no clue as to how to go about this question. Am i supposed to find the area under the curve? but how do i do that without y-axis numbers. am i supposed to look at the slopes?

Homework Statement Homework EquationsThe Attempt at a Solution I knew the answer was between A and B, but the inward curves and outward curves on the position time graph confused me , what exactly does it mean? -does A have an increasing velocity and then B has a decreasing velocity? I am...

Wow thanks so much. If this question asked for average speed, would it be the same? because i know avd speed = total distance / total time

the displacement and in this problem, the final distance and initial distance

Homework Statement A motorist drives north for 35.9min at 73.3km/hr and then stops for 15.4min. He then continues north, traveling 114.5km in 1.93hr. What is his average velocity? Homework Equations avg velocity = xf - xi / time The Attempt at a Solution 35.9 min * (1 hr / 60 min) = 0.5983...

okay i now understand that I got the normal force equation wrong it is: Fn = mg -T sin 45 why is the tension force negative? isn't Ty in the upward positive direction?

In the question, they stated the kinetic friction as 0.5 , which is what uk is. and frictional force, ff, is uk * normal force (fn), therefore Ff = uk * Fn ? right? I made the second equation as you said: Fy=sin 45 T -mg+ Fn =0 solved for T and got -0.9998 i must be doing something wrong...

Homework Statement Homework EquationsThe Attempt at a Solution Here is what i have done so far: Fx = cos 45 T - Ff =ma Fy=sin 45 T -mg+ Fn =ma I found ff= uk * Fn = 0.5 *sin 45 +mg fn = sin 45 +mg Isolated for T in the x and y: Tx = ma + Ff / cos 45 = 13.404 Ty = ma +mg - Fn / sin 45 =...

oh man... i totally messed up there, thank you so much for the correction! m2 will then = 9012 (10012 kg)(0 m/s) =m1v1 + m2v2 0= (1000 kg)(112 m/s)+ (9012 kg) (v2) v2 = -12.43 m/s

so would it be : pi=pf mivi = m1v1 + m2v2 (10012 kg)(0 m/s) =m1v1 + m2v2 0= (1000 kg)(112 m/s)+ (12 kg) (v2) v2 = -9333.3 m/s

Homework Statement The mass of a spaceship is 10012 kg. The spaceship is at rest. Then one part of the ship with a mass of 1000 kg is ejected and emerges with a speed of 112 m/s. What is the speed of the other part? Homework EquationsThe Attempt at a Solution I tried: pi=pf mivi=mfv2 10012...