Because equilibrium implies the acceleration is zero which must mean the velocity of the object experiencing zero net acceleration is either zero or some other constant unchanging number. However, zero is the state of rest, but that's not the only possibility. See? Ya know, if you were looking...
Yes, but the question refers to the limit rules. This is what I am asking: lim (x->∞) [ln(x^(1/x))]= ln(lim(x->∞) [(x^(1/x))]) = ln(1)??
To put it into words: Can the limit as x approaches infinity of [ln(x^(1/x))] be equal to the natural log of the limit as x approaches infinity of...
Homework Statement
If lim (x->∞) [ln(x^(1/x))]=0 and lim (x->∞) x^(1/x)=1, then does this
=>
lim (x->∞) [ln(x^(1/x))]= ln(lim(x->∞) [(x^(1/x))]) = ln(1)??
Homework Equations
lim (x->∞) [ln(x^(1/x))]=0 and lim (x->∞) x^(1/x)=1
The Attempt at a Solution
lim (x->∞) [ln(x^(1/x))]=...
I think doing this is the way to go, because the path difference depends on the difference in lamda between two light waves that interfere with one another. Forget the diffraction idea. I'm so used to thinking about these experimental type concepts with the assumption that the wavelength has to...
Actually, your first part is correct, but as far as the second part,
Here's an idea I had in mind:
Since we know m=dsin(θ)/λ for all maximas, then you could simply find the intensity at the maximas by replacing I(θ)=4I0cos2(∏dsin(θ)/λ) with I(θ)=4I0cos2(∏m)
Just an idea.
Also what...
Well, when this marble circulates, you would suspect that a normal force and a centripetal force as well as weight would exist to keep the marble in circular motion, however, at that Q point, only centripetal force and normal force exists in the x direction.
Just use decomposition to partial fractions actually.
have this:
A/3x-1 + Bx+C/x^2+1 as your premise...
Now if 11x^2-14x+9/(3x-1)(x^2+1) = A/3x-1 + Bx+C/x^2+1, then
11x^2-14x+9=A(x^2+1) + (Bx+C)(3x-1)
11x^2-14x+9=Ax^2 + 1 + 3Bx^2 + Bx + 3Cx + C...
A + 3B=11
A + C=9
B + 3C=-14 so on and...
I say decelerated, because, initially, the kite has a tension and in equilibrium, but when the weight exerts a force on the kite, the kite moves with some force that will accelerate the kite to move down y axis, yet somehow the kite stops. I suspect that there then would exist a deceleration...
You know what doesn't make sense though...If the y-component of the tension decreases with smaller angles, how does the rope deceleration in the y direction when the bird decides to sit down. We know this y component decelerated from 50 to 30 degrees
What's wrong with your thoughts? I don't see anything wrong. Perhaps, you are just wanting someone to elaborate on more dynamics of this situation. In that case, you would find the net force by knowing the angle and some trig. You know about it?
I am very weak at circuits and I wish my physics II teacher could gives us better insight to this stuff, however, here is a thought: Initial charge goes from high potential, but when it hits the inductor, the induced current is supposed to oppose it right? So, it never actually gets through that...