# An Implication of a limit rule

1. Sep 13, 2012

### Rayquesto

1. The problem statement, all variables and given/known data

If lim (x->∞) [ln(x^(1/x))]=0 and lim (x->∞) x^(1/x)=1, then does this

=>

lim (x->∞) [ln(x^(1/x))]= ln(lim(x->∞) [(x^(1/x))]) = ln(1)??

2. Relevant equations

lim (x->∞) [ln(x^(1/x))]=0 and lim (x->∞) x^(1/x)=1

3. The attempt at a solution

lim (x->∞) [ln(x^(1/x))]= ln(lim(x->∞) [(x^(1/x))] = ln(1)

2. Sep 13, 2012

### SammyS

Staff Emeritus
Just what is the question?

You do realize that ln(1) = 0, don't you ?

3. Sep 13, 2012

### Rayquesto

Yes, but the question refers to the limit rules. This is what I am asking:

lim (x->∞) [ln(x^(1/x))]= ln(lim(x->∞) [(x^(1/x))]) = ln(1)??

To put it into words: Can the limit as x approaches infinity of [ln(x^(1/x))] be equal to the natural log of the limit as x approaches infinity of [(x^(1/x))] since lim (x->∞) [ln(x^(1/x))]=0 and lim (x->∞) x^(1/x)=1?