Recent content by regnar

  1. R

    Volume of H2 gas from 25.8 g Zn and 124.7 mL of 6.0M HCl at 825 mm Hg and 42°C

    Yes, thank you. I converted everything to proper units before I did anything. Thank you for your help.
  2. R

    Volume of H2 gas from 25.8 g Zn and 124.7 mL of 6.0M HCl at 825 mm Hg and 42°C

    So, I find the moles of H2 and then plug that in for "n" in the equation and solve for V and that should be my answer?
  3. R

    Volume of H2 gas from 25.8 g Zn and 124.7 mL of 6.0M HCl at 825 mm Hg and 42°C

    Oh, I thought because that Zinc had the least amount of moles therefore making it the limiting reagent, but your reasoning makes perfect sense. Now that we have the limiting reagent, where do we go from there? I was told that have to use PV=nRT and work our way to liters of H2.
  4. R

    Volume of H2 gas from 25.8 g Zn and 124.7 mL of 6.0M HCl at 825 mm Hg and 42°C

    I found HCl to be in excess and Zinc to be the limiting reagent.
  5. R

    Volume of H2 gas from 25.8 g Zn and 124.7 mL of 6.0M HCl at 825 mm Hg and 42°C

    Oh, I'm sorry I forgot to put the reaction: 2 HCl + Zn ==> ZnCl + H2
  6. R

    Volume of H2 gas from 25.8 g Zn and 124.7 mL of 6.0M HCl at 825 mm Hg and 42°C

    124.7mL of a 6.0M solution of HCl is placed in a container with 25.8 grams of zinc metal. at 825mm Hg and 42*C, what volume of H2 gas can be produced from this reaction? PV=nRT; R=0.0821 L*atm/mols*K I don't if this is right but I decided to convert 25.8g of Zn into moles and then...
  7. R

    Pest eradication: finding daily fly release for steady population of 20,000

    I don't understand anything about this question: In a pest eradication program, N sterilized male flies are released into the general population each day, and 90% of these flies will survive a given day. A) Show that the number of sterilized flies in the population after n days is N +...
  8. R

    Evaluating the improper integral of ln(4x)/√x from 0 to 1

    I'm not sure what you mean or where t^2 came from.
  9. R

    Evaluating the improper integral of ln(4x)/√x from 0 to 1

    I've been stuck on this problem for quite some time and I get as far as setting up the problem. They are asking me to evaluate this integral: \int_0^1{\frac{(6ln4x)}{\sqrt{x}}dx and I get as far as: \lim_{b \to 0^+}{6\int_b^1{\frac{(ln4x)}{\sqrt{x}}
  10. R

    Volume of solid from rotating y=x³ and x=y³ about x=-1

    Ohh, okay thank you very much. Also, thank you for clarifying the differences between disk and washer method.
  11. R

    Volume of solid from rotating y=x³ and x=y³ about x=-1

    I'm working with 0 and 1 but I also tried -1 and I got a negative answer unless I did that wrong which I'm not sure.
  12. R

    Volume of solid from rotating y=x³ and x=y³ about x=-1

    Im sorry, but that is the exact statement our teacher has given us.
  13. R

    Volume of solid from rotating y=x³ and x=y³ about x=-1

    yes, I solved for x for y=x^3 and then set them equal to each other
  14. R

    Volume of solid from rotating y=x³ and x=y³ about x=-1

    It doesn't specify but I'm guessing -1. I also set each function equal to each other and got 0 and 1.
  15. R

    Volume of solid from rotating y=x³ and x=y³ about x=-1

    I tried what you said and I got the same answer, but here is the exact question: "Find the volume of the solid obtained by rotating the region bounded by and about the line x = -1."
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