Can substitution help solve this improper integral?

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SUMMARY

The discussion focuses on evaluating the improper integral \(\int_0^1{\frac{(6\ln(4x))}{\sqrt{x}}dx\). The participant successfully sets up the integral and identifies the substitution \(t = \sqrt{x}\) or equivalently \(t^2 = x\) as a method to simplify the evaluation. This substitution is crucial for transforming the integral into a more manageable form, allowing for easier computation of the limit as \(b\) approaches \(0^+\).

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regnar
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I've been stuck on this problem for quite some time and I get as far as setting up the problem. They are asking me to evaluate this integral:

\int_0^1{\frac{(6ln4x)}{\sqrt{x}}dx and I get as far as:

\lim_{b \to 0^+}{6\int_b^1{\frac{(ln4x)}{\sqrt{x}}
 
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Substituting x = t^2 seems to work...
 
I'm not sure what you mean or where t^2 came from.
 
It's called substitution.

The substitution is t=\sqrt{x} or t^2 = x
 

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