Can substitution help solve this improper integral?

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I've been stuck on this problem for quite some time and I get as far as setting up the problem. They are asking me to evaluate this integral:

\int_0^1{\frac{(6ln4x)}{\sqrt{x}}dx and I get as far as:

\lim_{b \to 0^+}{6\int_b^1{\frac{(ln4x)}{\sqrt{x}}
 
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Substituting x = t^2 seems to work...
 
I'm not sure what you mean or where t^2 came from.
 
It's called substitution.

The substitution is t=\sqrt{x} or t^2 = x
 

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