Okay, is this correct:
We can deduce that it'll be half the time from my reasoning in the first post.
the y-axis equation we need to use is: Δy = vot + ½at2
since vo = 0, Δy = ½at2,
if we apply t/2 we get Δy = ½a(½t)2 =(¼)½at2, so we'll end up with ¼*Δy, giving us 3/4H from the ground.
Is this...