- #1
reshmaji
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Homework Statement
Two buildings A & B are each of height H as measured from the ground & are located a distance L apart. A tennis ball is shot horizontally with a velocity vo from building A such that it just hits the bottom of building B before hitting the ground. If building B is moved to half the distance (1/2)(L) & the ball is launched with the same horizontal velocity, where on building B does it hit the side, measured from the ground?
Homework Equations
I think they are:
x-xo = (vocos(theta))t
y-yo = (vosin(theta))t - 1/2(g)t2
The Attempt at a Solution
Where the ball would be at L/2 = x/2 & results in t/2 because x is proportional to time in the equation.
So apply half the time to the y-axis equation, but since it's 2 terms with different degrees of t (one is t1, the other t2) I'm not sure what I can assert about how this effects y.