1. The problem statement, all variables and given/known data Two buildings A & B are each of height H as measured from the ground & are located a distance L apart. A tennis ball is shot horizontally with a velocity vo from building A such that it just hits the bottom of building B before hitting the ground. If building B is moved to half the distance (1/2)(L) & the ball is launched with the same horizontal velocity, where on building B does it hit the side, measured from the ground? 2. Relevant equations I think they are: x-xo = (vocos(theta))t y-yo = (vosin(theta))t - 1/2(g)t2 3. The attempt at a solution Where the ball would be at L/2 = x/2 & results in t/2 because x is proportional to time in the equation. So apply half the time to the y axis equation, but since it's 2 terms with different degrees of t (one is t1, the other t2) I'm not sure what I can assert about how this effects y.