Recent content by rohitarura

Thanks Sir(sorry). Just a bit more confusion But \omega=kt which is not constant as u took in previous post..,i.e., it has an angular acceleration Then how to explain it?? Thank you once again...

i couldn't understand only the 1st 3 expressions of z , r, and theta that u have wrtten, in them, they can be written only if there is a linear relation between z and t', r and t'.so how can we say there is linear relation between them? Sorry Sir, it may be a silly question but only that is...

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Finally, now I have got the opportunity to sit on a PC.Earlier, i only add access through mobile. If vz is the velocity along the vertical axis of the cone, \omega be the angular velocity = kt z be the z coordinate w.r.t. the tip of the cone. r be the radius of its path in cone So...

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We have to neglect gravity and any other force like friction, air drag are to be neglected.. The particle starts at t=0 with r(0) radius of cone. And it moves in a spiral path such that radius of spiral keeps increasing or it moves towards open side of the cone.. What i am most confused...

A particle moves on the surface of right circular cone of semi cone angle alpha, coaxial with z axis along a helical path of fixed pitch L starting from some r(0) radius. The angular velocity of the particle omega varies linearly with time, omega=kt. Determine velocity and acceleration of the...

Thank you very very much Sir.I'm very satisfied with your valuable views...Thanks

It tells that it is not necessary that the acceleration of A always be less or equal to the acceleration of B...But my fellows says the opposite?He says if 1 force is pulling such a system then acc. of the block A can't be greater than that of the block on which the force is applied i.e.,block B??

Earlier i accidentally took its opposite Taking,kx=4N,will make it..

Ya, kx=1N? So, what does this imply?

But, the forces on each keep varying?? We can have the equations, 4-kx=2aB kx=aA k being the unknown spring constant,and x is extension in it.. If we can prove, a(B)-a(A)=2-kx/3 can be negative then its done...

Only one force acts and that on B only.

Homework Statement Question : two masses MA = 1 kg and MB = 2 kg are connected by a massless spring as shown in figure. A force of 4 N acts on the 2 kg mass. http://www.vidyamandir.com//displayImageServlet?appletImgId=8a7b221f1fcc7894011ff9cccfe412f0 Is it necessary that the acceleration of A...