Recent content by rottentreats64

i have a computer that alwaysd worked fine but now when i enter certain folders the whole computer freezes and then everythign restarts?

k thank you

3. On a ski weekend in Colorado, Bob, whose mass is 75kg, skis down a hill that is inclined at an angle of 15º to the horizontal and has a vertical rise of 25.0m. How much work is done by gravity on Bob as he goes down the hill for this problem i thought you had to use sohcahtoa to find out...

4. At Six Flags in Massachusetts, a ride called the Cyclone is a giant roller coaster that ascends a 34.1m hill and then drops 21.9m before ascending the next hill. The train of cars has a mass of 4727kg. a. how much work is required to get an empty train of cars from the ground...

i really have no clue what to do in this problem since there's a measurement for the dent...what formula am i supposed to use for this?4. During an autumn storm, a 0.012kg hail stone traveling at 20.0m/s made a 0.20 cm deep dent in the hood of Darnell’s new car. What average force did the car...

so now my answer would be: Therefore when 270 million people jump at the same time the Earth will move at 276851851851851.85 m/s.

ohh yea so then the net force would have been 80x270,000,000

than doesn't 5.98x10to the 24 equal 5980000000000000000000000?

yea but i thought it was focusing on the Earth and she gave me...oh wait the question didnt paste into the topic correctly...its supposed to be 5.98x10 with and exponent of 24 thats where i got that big numba lol

2. If 270 million people in the United States jumped up in the air simultaneously, pushing of Earth with an average force of 800N each for a time of 0.10s, what would happen to the 5.98 x 1024 kg Earth? And this is what i wrote: Basically why I did was try to find out the velocity, to see if...

is that right?

The normal force is the same as the gravitational force, so Fnorm= 80N. Then I found out the mass by using the formula M=w/gàM=80n/10, the mass is 8kg. Then to find the net force you just do 50n (Fapp) – 10 N (Ffric) and you find out the net force is 40N. Then with this I was able to find the...

An applied force of 50 N is used to accelerate an object to the right across a frictional surface. The object encounters 10 N of friction. Use the diagram to determine the normal force, the net force, the mass, and the acceleration of the object. (Neglect air resistance.) this is the image she...

oh lol, i basically had no clue what to do for the second problem so i was guessing friction was involved

thanks but here's the question with the second problem, how do i know the friction? is there a formula i could use for it? and i don't undersatnd how would i could find the force that the breaks applied...could an1 explain this concept to me please?