Calculating Work Done by Gravity on a Ski Slope

  • Thread starter Thread starter rottentreats64
  • Start date Start date
  • Tags Tags
    Gravity Work
Click For Summary
SUMMARY

The work done by gravity on Bob, who has a mass of 75 kg and skis down a hill with a vertical rise of 25.0 m at an angle of 15º, can be calculated using the formula W = mgh, where g is the acceleration due to gravity (approximately 10 m/s²). Thus, the work done by gravity is 75 kg * 10 m/s² * 25.0 m, resulting in 18,750 Joules. Alternatively, one could calculate the work using the component of gravitational force along the incline multiplied by the length of the incline, but the vertical height provides a direct and simpler calculation.

PREREQUISITES
  • Understanding of gravitational force and its calculation (mg)
  • Basic knowledge of trigonometry, specifically SOHCAHTOA
  • Familiarity with the concept of work in physics (W = Fd)
  • Knowledge of incline planes and their properties
NEXT STEPS
  • Explore the concept of gravitational potential energy and its relation to work done
  • Learn about inclined planes and the forces acting on objects moving along them
  • Study the derivation and application of the work-energy theorem
  • Investigate the effects of different angles of inclination on work done by gravity
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of work and energy in gravitational contexts.

rottentreats64
Messages
19
Reaction score
0
3. On a ski weekend in Colorado, Bob, whose mass is 75kg, skis down a hill that is inclined at an angle of 15º to the horizontal and has a vertical rise of 25.0m. How much work is done by gravity on Bob as he goes down the hill

for this problem i thought you had to use sohcahtoa to find out what the hypotnuse is but then i thought all you had to do is 10*the distance 25 but I am not sure which is right?
 
Physics news on Phys.org
rottentreats64 said:
3. On a ski weekend in Colorado, Bob, whose mass is 75kg, skis down a hill that is inclined at an angle of 15º to the horizontal and has a vertical rise of 25.0m. How much work is done by gravity on Bob as he goes down the hill

for this problem i thought you had to use sohcahtoa to find out what the hypotnuse is but then i thought all you had to do is 10*the distance 25 but I am not sure which is right?

It is enough to multiply the force of gravity, mg, with the height of the hill. You'd get the same result if you multiplied the component of the force of gravity along the incline with the length of the incline (i.e. the hypothenuse).
 
k thank you
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K
Replies
5
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
11
Views
6K
  • · Replies 12 ·
Replies
12
Views
4K
Replies
15
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K