Recent content by saac

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    Finding the Collision Point for Two Walking Persons with Different Accelerations

    ok makes sense. however, i do not understand how to utilize the accelerations? would the equation look like this: x/.3=88-x/.2?
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    Finding the Collision Point for Two Walking Persons with Different Accelerations

    So t1=t2 . Would velocity be calculated for A & B? and then find the displacement for each?
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    Finding the Collision Point for Two Walking Persons with Different Accelerations

    Homework Statement Two people start from rest at 88m apart and walk directly toward each other. Person A has a magnitude of .3m/s^2, while person B has a magnitude of .2m/^2. Relative to person A's starting point, where do the people coincide? Homework Equations How to determine...
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    Kinematic One-D Problem: Calculating Total Distance Run by Dog in Morning Run

    Well you are right- It is an art. I'll keep trying, although the struggle will never end...btw you must have oodles of patience to deal with all the noob questions, or more specifically, the noobs doing the questions.
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    Kinematic One-D Problem: Calculating Total Distance Run by Dog in Morning Run

    Ah damn slightly shocked i didn't notice that. so dog is moving for 1600s at 4.5m/s. d=1600s*4.5m/s=7200m Certainly is a time consuming and painful shift. Thanks though!
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    Kinematic One-D Problem: Calculating Total Distance Run by Dog in Morning Run

    so find the time for both? t=4000/2.5= 1600 & t=4000/4.5=888.9 then the difference between the two, 1600-888.9=711.1. I'll use this time to find the dogs distance? 711.1*4.5...and the rest is the same a my last post. my apologies for my complex "reasoning". got to work out the bad before you...
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    Kinematic One-D Problem: Calculating Total Distance Run by Dog in Morning Run

    I am not sure how to word this but here's what i got...1777.75(distance the women is from the river once the has arrived)/2.5m/s(her rate)=711.1s(time it will take for her to arrive). Then i used that time to solve for the dogs D- d=4.5m/s*711.1s= 3199.95m. If i take this distance and add to it...
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    Kinematic One-D Problem: Calculating Total Distance Run by Dog in Morning Run

    So would the distance the dog has to travel 4000m-2222.25(where women is when dog reaches river) So d=4.5m/s*888.9s? that brings me back to the total distance. Or would d=4.5m/s*395.1s? the 395.1s obtained by taking 4000m-2222.25m=1777.75m then t=1777.75m/4.5m/s=395.1s? Am I on the right...
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    Kinematic One-D Problem: Calculating Total Distance Run by Dog in Morning Run

    Homework Statement A women and her dog are out for a morning run to the river, which is located 4km away. The women runs at 2.5m/s in a straight line. The dog is unleashed and runs back and forth at 4.5m/s between his owner and the river, until the women reaches the river. What is the total...
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    How to Determine the Distance Between Deer Using Vectors and Cosine Law?

    Thanks for the replies but I've had to move on as the class is quickly progressing
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    How to Determine the Distance Between Deer Using Vectors and Cosine Law?

    So i have drawn what i think is correct. Do i now separate the large triangle into two separate ones and then solve Hypotenuse for triangle A-B?
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    How to Determine the Distance Between Deer Using Vectors and Cosine Law?

    Vector and cosine law?? Homework Statement Three deer, A, B, and C, are grazing in a field. deer B is located 62m from deer A at an angle of 51 north of west. deer C is located 77 degree north of east relative to deer A. The distance between deer B and C is 95m. What is the distance between...
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