Recent content by sabak22

Homework Statement The diagram below depicts an RC-circuit where C = 3.45 F, = 29.0 , = 28.0 , and = 3.00 Volts What is the current through immediately after the switch S is closed? 1.03×10-1 A What is the current through immediately after the switch S is closed? 1.07×10-1 A What...

Yay I got it, so i did U=(1/2)Q/C^2 which gave me = 9.57*10^-5 Thank you very much gneill. just one quick question though, how will I know what the new voltage across the capacitor is after the battery has been disconnected? Just for my own knowledge.

wait gneill, its not the capacitance theyre asking me to enter theyre asking me to enter the energy stored after the gap has changed! I tried applying U=(1/2)CV^2 Which gives me 4.96*10^-5 J. But its still incorrect. what am i doing wrong? seems right to me

Yes gneill there is more stuff to it but i thought it wouldn't be important, but i guess it is: b)Now the plates of the charged capacitor are pulled apart with the voltage source already disconnected. - The energy stored in the capacitor: Increases. an then in c theyre asking for teh new...

really sorry about that. I didnt realize

umm, would it make sense if my new capacitance was now 2.345*10^-9 F?

Homework Statement Three capacitors C1–C3, all initially uncharged, are placed in the circuit show above. The capacitances are C1=15.2 μF, C2=9.8 μF, C3=4.4 μF, and the battery voltages are V1=20 V, V2=20 V, V3=5 V. What is the magnitude q1 of the charge on capacitor C1 once equilibrium...

yup I know, as distance increases Capacitance decreases. so in this case my capacitance will decrease because gap is now 10mm.

Homework Statement A capacitor is completely charged with 670 nC by a voltage source that had 200 V. What is its capacitance?==== 3.35×10-9 F 9(I got this y doing Q/V) The initial air gap of the capacitor above was 7 mm. What is the stored energy if the air gap is now 10 mm? Now...

Okay this is what I am doing: I3= I1+I 2 E+6-11(I3)-2= 0 ----> E+4-11(I3)=0 8+6-11(I3)-15I2=0 14-11(I3)-15I2=0 I3= 1.27-1.36I2 How do I find E?? I am so close! I know it

I may sound stupid, but I honestly have no idea how the Vab could help me with this. I calculated the current flowing from b to a, which gives me 1A...does this help me in any way? This assignment is due in 8 hours!

Homework Statement A DC circuit which includes Emfx of unkown magnitude and orientation, at the location indicated is shown below. Note the 'ground' (V=0) in the circuit. The potential between 'b' and 'a', Vb-Va, is measured to be 2.00 V. a) The magnitude of Emfx is: b) Calculate...

here are my attempts: First i made 4 different loops. each one of them looking like this by using Kirchoff's current law: A) 19-9I3-6I4+7-5I1=0 B) 7-5I1-16I2=0 C) 7-5I1+19-9I3-6I4=0 D) 19-9I3-6I4+16I2=0 But now I feel like I am stuck I don't know what to do. I don't even know if I...

https://www.physicsforums.com/attachments/39765 a) Calculate the current through the 5Ω resistance. Use '+' sign for the current directed from right to left, and '-' sign if the current flows from left to right. b) The magnitude of the potential at 'a' is? Please help me with the two...

Nvm got it! i was quite simple.