Recent content by saiyaex
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How can the value of the constant, 1240, in the Duane-Hunt relation be verified?
Homework Statement Just going over some practice questions, and one of them is: 1. Verify the value of the constant, 1240, in the Duane-Hunt relation. Homework Equations E(eV) = 1240/lambda(nm) The Attempt at a Solution I know it is used as a quick method in finding how much...- saiyaex
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- Replies: 1
- Forum: Introductory Physics Homework Help
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Coulombs Law. Calculate Charge Magnitude and Direction
Thank you again gneill. I have now arrived at the same answer as the OP. I was a little confused with the quadrants but I figured it out.- saiyaex
- Post #8
- Forum: Introductory Physics Homework Help
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Calculating Electric Force on an Electron Near a Point Charge
the direction would be to the left towards the charge, right?- saiyaex
- Post #11
- Forum: Introductory Physics Homework Help
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Work done to move a test charge
oh okay! simple enough. thanks a bunch.- saiyaex
- Post #14
- Forum: Introductory Physics Homework Help
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Work done to move a test charge
do I multiply the test charge with 6.242 × 10^18 e using millikan's relationship?- saiyaex
- Post #12
- Forum: Introductory Physics Homework Help
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Work done to move a test charge
1.60217646 × 10-19- saiyaex
- Post #11
- Forum: Introductory Physics Homework Help
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Work done to move a test charge
For this very same question above, how would I determine the electrons that were gained or lost from the test subject to create the charge?- saiyaex
- Post #9
- Forum: Introductory Physics Homework Help
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Coulombs Law. Calculate Charge Magnitude and Direction
Thanks gneill, I just seem to be lost and/or over thinking this. I know the direction caused by the repulsive force of q3 is up. For q2 I broke it up into it's x and y components as you suggested (converting the cm lengths to meters): x-component: -(2.7 x 10^-23)(0.4/0.5) = -2.6 x 10^-23...- saiyaex
- Post #6
- Forum: Introductory Physics Homework Help
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Coulombs Law. Calculate Charge Magnitude and Direction
I'm working on this same problem. I've calculated individual force that q2 and q3 are inflicting on q1, and I've calculated the angles of A, B, and C of the triangle. I know I now have to use trig: 2F = force of q2 on q1 3F = force of q3 on q1 Fnet^2 = (2F)^2 + (3F)^3 - 2(2F)(3F)cos(126.9...- saiyaex
- Post #4
- Forum: Introductory Physics Homework Help