Turns out I just needed to use the vertical post/hand as the axis of rotation, giving me a torques equation of:
0.2025 * 2.20kg * 9.8 = Torques CW
(torque caused by the sign) = (torque provided by the hand to keep the system in static equilibrium)
... giving me an answer of -4.3659, negative...
Hi!
I can't find out if my answer for the force of the hand is correct because the question requires both parts to be entered to tell me if its right.
When you say the torque is in the form of a couple, does this mean that there is some horizontal force acting on the vertical bar I need to...
Homework Statement
You are holding a sign as shown below. The sign (including the horizontal bar it hangs from) has a mass of 2.20 kg and is 40.5 cm wide. The sign is hanging from a 1.03 m tall, 4.46 kg vertical post. The sign is symmetric with a uniform mass distribution as implied by the...