I'm having trouble with this problem. I did: FTcosθ-mg= 0, solving for FT, getting FT= mg/cosθ. Then, along the x-axis, F-FTsinθ=0, solving for F, getting F= mgtanθ. Not sure how to go about it from here. What is the direction of the displacement?
Oh, got it. I simply assumed that if μA<μB, then the blocks would end up touching each other and have the same acceleration;
I see now that's not the case. I got aA, 2= g(sinθ- μAcosθ). Thanks for your quick response and help, Doc Al!
1. Two blocks made of different materials connected together by a thin cord, slide down a plane ramp inclined at an angle θ to the horizontal. The masses of the blocks are mA and mB and the coefficients of friction are μA and μB.
PART A
If μA < μB, determine a formula for the acceleration of...