Finding Acceleration of Two blocks connected by a string.

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SUMMARY

The discussion focuses on calculating the acceleration of two blocks connected by a string on an inclined plane, considering different coefficients of friction. For Part A, the correct formula for the acceleration of block A when μA < μB is aA, 1 = (mAgsinθ + mBgsinθ - AmAgcosθ - μBgcosθ) / (mA + mB). In Part B, when μA > μB, the acceleration formula simplifies to aA, 2 = g(sinθ - μAcosθ), indicating that the blocks do not necessarily have the same acceleration. The misunderstanding arose from incorrectly assuming that the blocks would touch and share acceleration.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with inclined plane physics
  • Knowledge of friction coefficients and their implications
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the effects of varying coefficients of friction on block motion
  • Learn about tension in strings and its role in connected systems
  • Explore advanced problems involving multiple blocks on inclined planes
  • Investigate the implications of different mass ratios on acceleration
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Physics students, educators, and anyone interested in mechanics, particularly those studying dynamics involving friction and inclined planes.

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1. Two blocks made of different materials connected together by a thin cord, slide down a plane ramp inclined at an angle θ to the horizontal. The masses of the blocks are mA and mB and the coefficients of friction are μA and μB.

GIANCOLI.ch05.p021.jpg

PART A
If μA < μB, determine a formula for the acceleration of block A in terms of mA, mB, and θ.
PART B
If μA > μB, determine a formula for the acceleration of block A in terms of mA, mB, and θ.


3. I got Part A right, of which aA, 1= (mAgsinθ+mBgsinθ-AmAgcosθ-μBgcosθ)/(mA+mB)

For Part B, I attempted it to solve it, and got the same answer as I did in Part A, yet MasteringPhysics says this is incorrect. Am I doing anything wrong? "The correct answer does not depend on the variables: mA, mB, or μB. "

Thanks for the help in advance.

 
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Hint: Do the blocks have the same acceleration?
 
Oh, got it. I simply assumed that if μAB, then the blocks would end up touching each other and have the same acceleration;

I see now that's not the case. I got aA, 2= g(sinθ- μAcosθ). Thanks for your quick response and help, Doc Al!
 

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