thanks for the discussion, i figured out why the answer is B already.
because the live and neutral are both connected to the live terminal in the plug, when the current comes in from the live, it will split into the earth and the live. so the appliance will still work as normal as the current...
it doesn't say. it just talks about the error in the plug. so the rest of the connections in the appliance is assumed normal i suppose, i.e the one end of the earth wire connects to the casing, the other end connects wrongly in the plug, earth to the live wire in the plug.
there are 4 options.
a) the fuse blows
b) the appliance becomes live
c) the appliance catches fire
d) the appliance doesn't work.
the answer given is b) , because the earth is connected with the live. but i would like to know why issn't option d) correct instead?
since the live and earth...
if this was a high school exam, what should i put as the answer?
the official exam answer given is "there is no change in PE when liquid is heated. only KE increases as temp rise."
my textbook says "KE & PE increases when liquid is heated and temp rises."
ok i am starting to understand.
"when a liquid is vaporising to gas, the temp remains constant. KE is constant, but PE of particles is increasing." We have to put in energy to separate the particles, resulting in more PE.
but then i saw another question that confused me again.
"when a liquid...
if the ball's velocity is 0 for even a single moment at the top, then the acceleration should be 0 right? v=0, a must be 0?
i understand how gradient of a v-t graph gives acceleration, like if v=0 for 1s, a = (0-0)/1 = 0.
but what if v =0 at only an instantaneous moment? not sure how does the...
The answer given is -10m/s2 because of constant downwards acceleration of gravity.
i would like to know why is it not 0 at its peak height. at the top, velocity is momentarily 0, since acceleration is the change in velocity, change in 0 = 0. so why issn't a = 0?
thanks
this is confusing. my textbook says in solids, each particle stores a large amount of PE due to strong intermolecular forces. in gases, due to negligible intermolecular forces, the PE is negligible.
so is this wrong?
the textbooks says PE is the attractive forces between each particle.
when...
oh so in a solid, the forces between particles are very strong, but the PE of the particles are weak.
in a gas, the forces between the particles are weak, but the PE is strong?
it decreases ?
but the KE model says solid have the greatest potential energy because the particles are close together, as opposed to gases where they are spread apart so their PE is negligible. Since it is going from gas -> liquid, shouldn't the PE increase?
this was the answer given by the teacher. is it wrong?
the potential dividing equation?
Vfixed = Vbatt x [ 600 / (600+Rvariable) ] ?
so it's like a 1/x curve?
The answer says it decreases but shouldn't it increase? according to the kinetic model, KE accounts for particle vibrations. PE accounts for the attractive forces between particles.
Since condensation means gas -> liquid, it means the particles become closer and hence the attractive forces...
I just saw a question saying there's an induced current in a dc motor. i always thought dc motors' electromagnetism is separate from the ac generators' electromagnetic induction? if there's really an induced current, how will the overall system work then? wouldn't the rotation be opposed?
also...
I have plotted the V-R graph.
when Rv is 600 ohms, Rf is also 600ohms, which means the voltage across both resistors should be split evenly at 3V each since batt is 6V.
however, from the graph, i noticed that Vf is 3.4V and Vv is 2.6V instead at 600 ohms.
i would like to know where did it...
so 30N of the 40N upwards force is used to counter the 30N of the weight, some work done by the upwards force is used to counter the work done by the weight.
and the other 10N is used to give the object KE?
so the net force gives the KE?
since some net force is used to counter air resistance...