Recent content by Simonnava

Quotient Rule Please see the attached file. You will see how the quotient rule is require to get that answer.

Sorry, I mean : You have to use the quotient rule!

You have to your the quotient rule!

try using the quotient rule for the derivation! You will get it!

Here is my concern, In my physics class I learned that a dipole moment always goes from the - charge to the + charge. But as I was reading my Organic Chemistry book, it says that the dipole goes from + to -! how can this be? P = Qd Does anyone know about this? Simon

answer exactly, my answer is the correct one.

The elementary charge is = 1.6X10^-19 C not 1.6x10^19 C

of course, I didn't draw the other tension on the other side because is understood.

2nd problem ok the hyp that you got is good. a^2 + b^2 = c^2 a= 16 b = .182 c = 16.001 using the formula. Good you got until this point. 2nd step= get the angle theta. (see diagram) 90-tan (16/.182) = theta step 3 = Get the tension by adding the Forces on the y axes. See diagram

First problem (sail boat) check the attachment Fx = F(east) - F(northwest)Xcos45 = -12339 N Fy = F(northwest)Xsin45 = 39739 N Fnet = Squareroot of (Fx^2 + Fy^2) then, Fnet = ma a = Fnet/mass = 3.4 m/s

1st step is to draw a gaussian surface 2nd step is to find the flux = EA = E 2(pi)(r^2) 3rd step is to find the charge from the equation, rho = Q/V ; Q = rho * Volume = (rho)[(2)(pi)(r^2)(d)] 4th step is to use gauss law, EA = Q/8.85X10^-12 and solve for E. Epsilon = 8.85X10^-12

is it stopped at the distance of 45 cm?