Recent content by Snape1830

Oh, right yeah, I just didn't put the decimal point in. Silly me. Thanks!

It would be 6.4, and it's wrong because I plugged in the answer and it said it was wrong.

.8 amps?

8? It seems wrong for some reason

Ok! So now part b how much power dissipated through a 10 ohm resistor. The power equation. P=IV or P=I2(r) or P= v2/R I tried a few answers but none of them work.

No? So it would be 1.6 A? And thanks for taking the time to edit the picture!

Kirchoff's loop rule? The current going in equals the current coming out. So do I find the current through of the parallel resistors and then add them up...because that comes out to 2 and 2 is wrong.

Oh, right, I misread the question. V=2(4) V=8 Volts

V-RI V=10(2) V=20 V V=20(2) V=40 V So across the 10 ohm resistors, the voltage drop is 20 V Across the 20 ohm resistor the voltage drop is 40 V? That 40 can't be right, though?

Just the two 10s? How do I find the voltage if I only have the resistors?

The three resistors in parallel? But to find current you need to know the voltage.

Well, 4+6=10. So... 20=10I I=2 A But 2 is wrong, so I don't know.

10, 10 and the 20 ohm resistor are in parallel. So the Rnet is 4 for those? So then do I just use V=RI to solve for current?

So 20 and 6 are in series? That's what I thought. I'm not really sure how to redraw it. Can you can just help me get the answer?

Ok...so how do I do the problem?