Recent content by ssarpal

There are a couple of problems with the same setup. On plugging in the values and solving for the integral, I am not getting the expected values of the force. Is there something wrong in the solution attached?

The answer that we were told turned out to be incorrect. Thanks.

I have attached my solution. Unfortunately, after plugging in the values, my answer is 4 times more than the expected one. What am I missing?

The section Kepler’s Second Law here describes the above equation. In this problem, ##\text{r = D, m = M and v = V}## What is the way to go about finding out ##\theta## as shown in Figure 13.21?

Yes, was wondering where it could be used, am not sure how though.

I think that means ##mu_1 = mv_1 +m_2v_2## where ##u_1## = 4 m/s and ##m_2## = 2 Kg Am not sure if ##v_1## and ##v_2## are needed to solve this?

Unfortunately, this is not the right answer.