Recent content by stannard97

But Fafter equilibrium=ktotal*x where Ftotal is F required to overcome initial tension+Fafter equilibrium so Ftotal-Initial Tension=ktotal*x

Calculate the initial tension of two springs in parallel by treating them as a single spring. Initial tension as in the force needed to begin extending the spring. Ktotal is the sum of individual spring constants and total force is shared between both springs.

Homework Statement How to calculate initial tension or pretension in a system of two parallel springs. F=5.33213N K1+K2=53.0597 x=0.095 Individual springs have initial tension of 0.25N so I would expect an answer of 0.5N but I can't get there. Homework Equations F=(k1+k2)x The Attempt at a...

That makes sense for a Hooke's law but I'm still not seeing it for harmonic motion. I guess I'll have to accept it anyway though, thanks for your help

I get that it's a constant its just that if you don't know about initial tension and use F=kx to work it out, you will get a slightly high value, not the true value. I just can't get my head round whether simple harmonic motion would give you the slightly high value or the real one. Think of a...

When it's at equilibrium, there's no net force. Gravity and tension are equal. If you stretch it, then you provide a force in the direction of gravity and tension increases equally so that when you let go of the spring the initial force is equal to change in tension and proportionate to...

I'm not too sure what you mean, would it be equal to kx?

Find the spring constant by timing simple harmonic motion. I have done a Hooke's law experiment already and found out about initial tension. What I learned was: force ≠ spring constant x displacement force = initial tension + (spring constant x displacement) So using F=kx would not give an...