Initial Tension Of Parallel Spring System

  • #1

Homework Statement


How to calculate initial tension or pretension in a system of two parallel springs.
F=5.33213N
K1+K2=53.0597
x=0.095

Individual springs have initial tension of 0.25N so I would expect an answer of 0.5N but I can't get there.

Homework Equations


F=(k1+k2)x

The Attempt at a Solution


Total force applied - Initial tension = (k1+k2)x
Total force applied - (k1+k2)x = Initial tension = 0.29?
 

Answers and Replies

  • #2
291
33
Could you please restate the problem exactly as it reads? And provide a drawing perhaps? Also, I have never seen the word pretension used that way. Ever.
 
  • #3
291
33
Those pretentious springs! Such over-inflated senses of self-worth!
 
  • #4
Could you please restate the problem exactly as it reads? And provide a drawing perhaps? Also, I have never seen the word pretension used that way. Ever.
Calculate the initial tension of two springs in parallel by treating them as a single spring. Initial tension as in the force needed to begin extending the spring. Ktotal is the sum of individual spring constants and total force is shared between both springs.
 

Attachments

  • #5
291
33
I would say that (k1 + k2)x - F = initial spring tension, not F - (k1 + k2)x.
 
  • #6
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Think about the initial state of the springs. The tension in them can be expressed as (k1 + k2)[x][/0] and then the force F further stretches the springs to the value (k1 + k2)x. Thus, (k1 - k2)x - F = initial tension.
 
  • #7
I would say that (k1 + k2)x - F = initial spring tension, not F - (k1 + k2)x.
But Fafter equilibrium=ktotal*x
where Ftotal is F required to overcome initial tension+Fafter equilibrium
so Ftotal-Initial Tension=ktotal*x
 
  • #8
291
33
Yeah that looks good. Thank you for clearly and concisely representing the quantities.
 

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