Recent content by stealthezio

Well almost , It seems as I have to take ev = v1 sinθ - v2 As by assigning each velocity a direction . Silly mistake by me. Thank you for the help.

Is this correct? ev = v1 sinθ + v2 then substitute as v2 sinθ = (ev-v1 sinθ) sinθ

Ok so I did this mv sinθ = Mv1 + mv2x ------------1 mv2x = velocity of m in x direction e = (v1 + v2) / v ev = v1 + v2 v2 = ev - v1 Now velocity in x direction for m will be v2 sinθ v2 sinθ = (ev - v1) sinθ -------2 substituting 2 in equation 1 mv sinθ = Mv1 + m sinθ (ev-v1) v1 =...

x direction

yes sorry it is.

No other external forces. Rest of the forces are from within the system.

Normal force from the ground? So we conserve momentum in x direction

perpendicular to the line of impact? or along the slide of wedge

momentum is always conserved that i know of.

1. In the figure shown , a ball of mass m collides perpendicularly on a smooth stationary wedge of mass M , kept on a smooth horizontal plane. If the coefficient of restitution is e , then determine the velocity of the wedge after collision. https://postimage.org/][/PLAIN] Given mass of ball...