Recent content by suppy123

nice logic...all i know that the pressure under the sea is equal to inside the balloon well u got any hint?

Homework Statement b) A spherical balloon is inflated to a diameter of 60.0 cm. Assuming that the gas in the balloon is of atmospheric pressure (101.3 kPa) and is at a temperature of 20.0 oC. The above balloon is then taken by a diver 25.0 m under the sea. The temperature of the seawater...

got it, a.b = axbx+ayby a.b= 20i*20i+7j*7j= 449

!? do i need to write the whole of that!?? 600j^2 + 210ij + 73.5j^2 600j.j + 210 i . j + 73.5j.j 600(1) + 210 (0) + 73.5(1) is this alright

Homework Statement A 3.00kg object has velocity 7.00j m/s. Then, a total force 12.0i N acts on the object for 5.00s. Find the final kinetic energy from 1/2mvf^2 = 1/2mvf . vf Homework Equations The Attempt at a Solution i got 1/2 * 3 * (20i+7j)(20i+7j) then 600j^2 + 210ij +...

heh:redface:

tim! i also want to know ur method :)

ln(vo/2) = -k/m*s + ln(vo) ln(vo)-ln(2)=-k/m*s + ln(vo) ln(2)m / k = s 0.69m/k = s :)

but it doesn't give any values except for the distance

- m/k = -vt+vc m/k=vt-vc

0?

but i don't know the t the left-hand side which is...?

∫mdv/v^2 = -m/v = -∫kdt ∫kdt= m/v

er, k= -ma/v^2 k=-m(dv/dt)/v^2 ∫kdt = -∫m(dv/dt)/v^2 dt = -∫m/v^2 dv = m/v

oo, but how do i find out the "t" from k or it is just -m/v = 0 ??