Homework Statement
f = \frac{1}{z(z-1)(z-2)}
Homework Equations
Partial fraction
The Attempt at a Solution
R1 = 0 < z < 1
R2 = 1 < z < 2
R3 = z > 2
f = \frac{1}{z(z-1)(z-2)} = \frac{1}{z} * (\frac{A}{z-1} + \frac{B}{z-2})
Where A = -1 , B = 1.
f = \frac{1}{z} *...
Inside the sine meaning, the argument of the 'arcsine' would only range from -1 to 1.
So I'm guessing you can't make the substitution because arcsin(infinity) = error?
I was testing for convergence of a series:
∑\frac{1}{n^2 -1} from n=3 to infinity
I used the integral test, substituting n as 2sin(u)
so here's the question:
when using the trig substitution, I realized the upperbound, infinity, would fit inside the sine.
Is it still possible to make...