Recent content by taishizhiqiu
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Graduate Grassmann number: a more rigorous treatment?
@protonsarecool Thanks for explaining ##[a, \eta]_+ = 0##. However, I think it is not the correct way to just write ##\eta## out of the overlap in, for example, ##\bra{1} \eta \ket{1} = \bra{1} \ket{0} - \bra{1} \ket{\eta} = - (- \eta) \bra{1} \ket{1} = \eta ##. I am not sure I can draw a...- taishizhiqiu
- Post #11
- Forum: Quantum Physics
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Graduate Grassmann number: a more rigorous treatment?
Thanks for the reply. ##a## is the annihilation operator of the state: ##a|1\rangle=|0\rangle##, ##\langle 0 | a = \langle 1 |## (I have already edited the original post for clarification). It is important to notice that Grassmann numbers are supposed to anticommute with annihilation and...- taishizhiqiu
- Post #3
- Forum: Quantum Physics
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Graduate Grassmann number: a more rigorous treatment?
Most textbooks on fermionic path integral only briefly introduce Grassmann numbers. However, I want a more systematic treatment to feel comfortable about this approach. For illustration, I have several examples here. Example 1: Consider a system with only one state, how to calculate ##\langle...- taishizhiqiu
- Thread
- Fermions Grassmann Path integral Rigorous Treatment
- Replies: 11
- Forum: Quantum Physics
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Undergrad What breaks time reversal symmetry in ferromagnets
I don't understand this. Can you show me an example?- taishizhiqiu
- Post #6
- Forum: Atomic and Condensed Matter
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Undergrad What breaks time reversal symmetry in ferromagnets
OK, I finally learned spontaneous symmetry breaking. However, I am stilled confused. Supposing two local minimum in ferromagnets, time reversal symmetry will transform one into another, both of which are ground states of the Hamiltonian. Thus, it seems that ##T## is actually commutable with...- taishizhiqiu
- Post #3
- Forum: Atomic and Condensed Matter
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Graduate Why is the Brillouin zone a torus?
Thanks for the suggestion.- taishizhiqiu
- Post #16
- Forum: Atomic and Condensed Matter
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Graduate Why is the Brillouin zone a torus?
Oh, yeah. I am sorry, ##\psi_{nk}##s do live in the same Hilbert space. However, in berry connection, we only use ##u_{nk}## and they do not satisfy PBC.- taishizhiqiu
- Post #14
- Forum: Atomic and Condensed Matter
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Graduate Why is the Brillouin zone a torus?
Hey, they satisfy different boundary conditions: ##\psi_{k}(x+R)=e^{ikR}\psi(k)##- taishizhiqiu
- Post #11
- Forum: Atomic and Condensed Matter
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Graduate Why is the Brillouin zone a torus?
So, in the original question, I said wave functions (##\psi_k##)can be identified at opposite edges of brillouin zone. However, since ##\psi_k## in different points of brillouin zone do not live in the same Hilbert space, I don't know whether we can define berry phase using ##\psi_k##.- taishizhiqiu
- Post #9
- Forum: Atomic and Condensed Matter
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Graduate Why is the Brillouin zone a torus?
Oh, I am sorry. You are right, but the question remains.- taishizhiqiu
- Post #5
- Forum: Atomic and Condensed Matter
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Graduate Why is the Brillouin zone a torus?
What's the difference between your equation and mine? They look the same!- taishizhiqiu
- Post #3
- Forum: Atomic and Condensed Matter
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Graduate Why is the Brillouin zone a torus?
Recently, topological concepts are popular in solid state physics, and berry connection and berry curvature are introduced in band theory. The integration of berry curvature, i.e. chern number, is quantized because Brillouin zone is a torus. However, I cannot justify the argument that...- taishizhiqiu
- Thread
- Brillouin Brillouin zone Solid state physics Topological insulators Torus
- Replies: 18
- Forum: Atomic and Condensed Matter
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Undergrad What breaks time reversal symmetry in ferromagnets
I am told that in ferromagnets, time reversal symmetry is broken. However, I don't know any hamiltonian terms in solid that can break time reversal symmetry. So is there a hamiltonian term I don't know or is there any subtlety in ferromagnets?- taishizhiqiu
- Thread
- Magnetism Symmetry Time Time reversal Time reversal symmetry
- Replies: 6
- Forum: Atomic and Condensed Matter
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Graduate Average momentum of energy eigenstates is always zero?
Why x is not a single-valued operator will lead to breakdown of the claim in my original post? After all, we can define x to be between ##-L/2## and ##L/2##.- taishizhiqiu
- Post #10
- Forum: Quantum Physics
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Graduate Matrix elements of non-normalizable states
According to bloch theorem, wave function in crystals should be like ##\psi_k(x)=e^{ikx}u_k(x)##, where ##u_k(x+a)=u_k(x)## and ##a## is lattice constant. So ##\langle u(k)|\partial_k|u(k)\rangle## should be something like ##\int u^*_k(x)\partial_k u_k(x)dx##, although it doesn't make sense...- taishizhiqiu
- Post #3
- Forum: Quantum Physics