Recent content by Tastosis

My V2 from the first equation is... V2 = (M1V1) / M1 + M2, where M1 = 0.02kg M2 = 50kg V1 = :confused:

I don't get it. I thought I can substitute V2 from the first equation to the second equation..since it has the same V2 because the collision was inelastic. Now I'm confused again :confused: lol

I finally get it..I think: From Conservation of momentum: V2 = (M1V1) / M1 + M2 Work-energy: MV12 + 2Wother = MV22 Substitute: MV12 + 2Wother = M [(M1V1) / M1 + M2]2

Oh, my bad. So W = Fd But back to the first equation, I have 2 unknowns, V2 and V1?

That's my problem, I don't know how to get the V1 of the bullet :confused: EDIT: My Wothers is the 0.80 N

Conservation of momentum: V2 = (M1 * V1) / M1 + M2 V2 = (0.02kg * 1 m/s) / 0.02kg + 50kg V2 = 0.0004 m/s Work-energy theorem: K1 + Wothers = K2 1/2 MV12 + Wothers = 1/2 MV22 V22 = [(0.02kg * (0.0004 m/s)2) + 2 * 0.80 N] / 0.02kg V22 = 80 m/s V2 = 8.9 m/s

Oh yeah. From where it stands, here is my equation (I'm still in conservation of momentum): M1V1 + 0 (since the block is initially at rest) = (M1 + M2) V2 How do I get V1 of bullet?

I'm stuck. How do I get the velocity initial of the bullet? Do I use the 0.80 N to solve for the time?

Thanks for the tips! So I use conservation of momentum to solve for Vf which I will use as Vi for the final answer?

Homework Statement A horizontal force of 0.80 N is required to move a mass M2 = 5kg across the surface with a constant acceleration. With the block initially at rest, a 0.02kg bullet M1 fired horizontally into the block causes the block (with bullet inside) to slide 1.5m before coming to rest...

50kg (1/12s) + M2 (1/18s) = 0 M2 = [50kg (1/12s)] / 1/18s M2 = 75kg Did I do it right?

50kg * x/12s+ M2 * x/18s = 50kg * x/12s + M2 * x/18s ?

I'm confused >.< So the equation I'm using is wrong?

Homework Statement Two skaters stand in the center of a circular rink of frictionless ice. When the skaters push on one another, they move apart along the same straight line. If the skater of mass m1 = 50 kg reaches the edge of the rink after 12 seconds and the other skater reaches the...

Sorry it took me long to get back to you guys... [PLAIN]http://img407.imageshack.us/img407/6095/73837542.jpg Do I cancel U2g? =3