Recent content by theoblivin8r
-
T
Help Me Calculate How high SuperMan can Jump
Thanks for the hint. I had missed that key information. I have to solve this using projectile motion and not energy so thanks anyway. I'll post questions if I have anymore.- theoblivin8r
- Post #3
- Forum: Introductory Physics Homework Help
-
T
Help Me Calculate How high SuperMan can Jump
Homework Statement This is a semester review. I am having trouble starting the second part of this question. It is well-know fact that Superman is "faster than a speeding bullet, more powerful than a locomotive, and able to leap tall buildings in a single bound." Assume his mass is 100kg. The...- theoblivin8r
- Thread
- Jump Superman
- Replies: 3
- Forum: Introductory Physics Homework Help
-
T
Mastering Physics, Finding the Compresssion of a Spring using Momentum.
F(x) your answers were incorrect according to Mastering Physics. I am having trouble understand how momentum does not come into play in this problem since it is in my momentum chapter. I blame my professor. Anyways, it is getting late and I don't have time to finish the problem. Thanks for your...- theoblivin8r
- Post #6
- Forum: Introductory Physics Homework Help
-
T
Mastering Physics, Finding the Compresssion of a Spring using Momentum.
This is another problem from the same homework set that I was working on earlier. Again I believe conservation of momentum is the key formula. Homework Statement An 8000kg freight car rests against a spring bumper at the end of a railroad track. The spring has constant k=3.2*10^5. The car is...- theoblivin8r
- Thread
- Mastering physics Momentum Physics Spring
- Replies: 6
- Forum: Introductory Physics Homework Help
-
T
Mastering Physics Help, Conservation of Momentum
Sorry, In my rush to complete the problem I got ahead of myself and forgot to correct my previous mistake. Well I fixed my error and found the new V1x and used it to calculate the V2y. Then I used the Pythagorean Theorem and found a velocity of 2.6*10^5 and it was correct. Now onto the...- theoblivin8r
- Post #8
- Forum: Introductory Physics Homework Help
-
T
Mastering Physics Help, Conservation of Momentum
By the way I have to go to work so I'll check back in around 6 hours. Thanks again.- theoblivin8r
- Post #6
- Forum: Introductory Physics Homework Help
-
T
Mastering Physics Help, Conservation of Momentum
Okay, this makes sense if you are talking about the 238U particle. I see my simple error in calculating the x-velocity. Here was my next attempt. V1x=2.0*10^7(cos34)=1.66*10^7m/s V1y=2.0*10^7(sin34)=1.12*10^7m/s Since there is no velocity in the y direction for the initial particle I...- theoblivin8r
- Post #5
- Forum: Introductory Physics Homework Help
-
T
Mastering Physics Help, Conservation of Momentum
Okay, I understand that I need to look at the conservation of momentum for both the x and y directions. Here was my next attempt. M1(V1x)+M2(V2x)=(M1+M2)Vfinal(x) M1(V1y)+M2(V2y)=(M1+M2)Vfinal(y) Using the angle 34 as given I calculated the initial velocities of the 4He particle...- theoblivin8r
- Post #3
- Forum: Introductory Physics Homework Help
-
T
Mastering Physics Help, Conservation of Momentum
Homework Statement A 238U nucleus is moving in the x direction at 4.5*10^5 m/s when it decays into an alpha particle 4He and a 234Th nucleus. 1.) If the alpha particle moves off at 34degrees above the x-axis with a speed of 2.0*10^7 m/s, what is the speed of the thorium nucleus? 2.)What...- theoblivin8r
- Thread
- Conservation Conservation of momentum Mastering physics Momentum Physics
- Replies: 7
- Forum: Introductory Physics Homework Help