Recent content by ThievingSix

Alright this is how i got the answer, please tell me if its the right way. I used the method Vagn suggested. Finding velocity at "X" v2 = u2 - (2gs) v2 = 02 - (2*9.8*0.5) v2 = -9.8 v = \sqrt{9.8} Finding KE at "X" KE = \frac{1}{2}\times m \times v2 KE = \frac{1}{2}\times 10 \times...

In class it was explained that at half way between a given distance Potential energy(PE) lost equals the Kinetic energy(KE) gained. OR PE Lost = KE Gained at 1/2 the distance. But when i do the math for it, it does not work out. What am i missing, i understand the concept but i can't prove...