Alright this is how i got the answer, please tell me if its the right way.
I used the method Vagn suggested.
Finding velocity at "X"
v2 = u2 - (2gs)
v2 = 02 - (2*9.8*0.5)
v2 = -9.8
v = \sqrt{9.8}
Finding KE at "X"
KE = \frac{1}{2}\times m \times v2
KE = \frac{1}{2}\times 10 \times...
In class it was explained that at half way between a given distance Potential energy(PE) lost equals the Kinetic energy(KE) gained. OR
PE Lost = KE Gained at 1/2 the distance.
But when i do the math for it, it does not work out. What am i missing, i understand the concept but i can't prove...