Recent content by tomlry

The unit of dx is length, so that means |ψ|2 has to be 1/length for the probability density to become dimensionless. |ψ| must then be [length]-1/2. Thank you :)

Oh, I see. |ψ|2 is a function and you will only get a probability if this function is integrated. I only have a wave function for a free particle ψ(x,0)=Ae-(x-x0)2/4a2eilx, where a and l are constants that I don't know the dimensions of.

|ψ(x,t)|2 is the probability density. Probabilities are dimensionless. What would the SI units of |ψ(x,t)| be, then? Also dimensionless?