Recent content by Troi Jones

Ok. So the speed of sound is 343 m/s. The wavelength formula equals velocity/ frequency. So wavelength should equal 343/425 which equals about 0.8071 m. Since I still have wavelength/2, that means I divide 0.8071/2 equalling 0.4035. So for my equation to solve for x= x|S1 - S2| = wavelength...

Oops my mistake but ok 6x is correct. So what do I use 6x for? Do i substitute for S1-S2 in S1-S2= wavelength/2?

After solving for x in S_1 - S_2, I get answer of 6x i think. But I'm not sure what to do next?

So should my equation for S2 be sqrt(3.05^2 + (3/2 + x)^2) and S1 be sqrt(3.05^2 +(3/2-x)^2) to solve for x?

Homework Statement Two loudspeakers are placed 3.00 m apart horizontally.They emit 425 Hz sounds, in phase. A microphone is placed d= 3.20 mid distant from a point midway between the two speakers, where an intensity maximum is recorded. (a) How far must the microphone be moved to the right to...

Update: I got the answer wrong. My answer was < 0.4242,0, -.9056>. The solution was <0.914,0, -0.407>. Not quite sure how to get to that answer but anyone feel free to explain if you understand.

Could you please elaborate on how you know the vector magnitude is 1 and how do you know the vector is pointing at theta below the +x-axis?

sorry though I posted it. The correct diagram to look at is B

Homework Statement A 0.5 kg block of ice is sliding by you on a very slippery floor at 2.5 m/s. As it goes by, you give it a kick perpendicular to its path. Your foot is in contact with the ice block for 0.0035 seconds. The block eventually slides at an angle of 24 degrees from its original...

Is this how my equation is suppose to be: ΔF = -kΔx = (0.43-2.3)= -(10)(xfinal - 3.0666)?

Ohhhhhh, that makes much more sense now. Thank you very much!

Sorry, I am seem to be a bit confuse with the statement of using the force equations to find the new position than using velocity. Do I have to manipulate the force equations and set them equal to delta r?

Homework Statement A spring has a relaxed length of 35 cm (0.35 m) and its spring stiffness is 10 N/m. You glue a 70 gram block (0.070 kg) to the top of the spring, and push the block down, compressing the spring so its total length is 12 cm. You make sure the block is at rest, then at time t =...