Recent content by Trousers

thanks it was in kJ

if I use 708 seconds it's still wrong

horse power A horse pulls a cart with a force of 180.0 N at and angle of 26.0o with respect to the horizontal and moves along at a speed of 6.0 km/hr. How much work does the horse do in 11.8 min? ok I use the equation Fcos(theta)d=W 6km/hr=1.67m/s 11.8min=708s so 708*1.67=1182 m...

x=18 is the solution. I can't believe it.

Find a Cartesian equation for the curve. 18=rcos \theta \frac{\ 18}{cos \theta}= \sqrt{x^2+y^2} how do I get rid of the cosine?

thank you.

that doesn't help me.

1. Let c be a positive number. a differential equation of the form dy/dx=ky^(1+c) Determine the solution that satisfies the initial condition y(0)=y(subzero) The solution is y(subzero)=(1)/((ckT)^(1/c)) but I can't understand how to find it. ok when i integrate dy/y^(1+c)=kdt, I get...