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Simple polar to cartesian conversion

  1. Mar 4, 2008 #1
    Find a Cartesian equation for the curve.
    [tex]18=rcos \theta[/tex]

    [tex]\frac{\ 18}{cos \theta}= \sqrt{x^2+y^2}[/tex]

    how do I get rid of the cosine?
     
  2. jcsd
  3. Mar 4, 2008 #2

    HallsofIvy

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    Don't divide by it! What is [itex]r cos(\theta)[/itex] in terms of x and y coordinates? In other words, x= ? , y= ? in polar coordinates.
     
  4. Mar 4, 2008 #3
    x=18 is the solution. I can't believe it.
     
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