Simple polar to cartesian conversion

Trousers · Mar 4, 2008

Find a Cartesian equation for the curve.
[tex]18=rcos \theta[/tex]

[tex]\frac{\ 18}{cos \theta}= \sqrt{x^2+y^2}[/tex]

how do I get rid of the cosine?

HallsofIvy · Mar 4, 2008

Don't divide by it! What is [itex]r cos(\theta)[/itex] in terms of x and y coordinates? In other words, x= ? , y= ? in polar coordinates.

Trousers · Mar 4, 2008

x=18 is the solution. I can't believe it.

Simple polar to cartesian conversion

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