Recent content by uber_dzl

i sense that i am completely off...i will rethink this and come back

i have a similar problem so i didnt want to start a new thread, i hope there arent any feelings of thread jacking, but my problem is that i have the force and the k constant and an original length but i need to find the final length. would it be the force added to the k * x or multiplied like...

wow! what a tedious mistake...it was the placement of the exponent and parenthesis that was wrong... thanx

is my issue the placement of sin(theta) in the equation before i solve for h?

((1/2)m(v^2)*sin(theta))=mgh...then ((1/2)m(v^2)*sin(theta))/mg=mgh/mg...then the m cancels leaving me with (v^2*sin(theta))/2g=h

i just did this exact problem in my homework and got the correct answer but i don't kno how to help without breaking a forum rule and giving u the answer

well you are starting from rest with U_i so it makes sense to me that what ever happens after would only be distributions of the energy between kintetic and potential so I would set the equation to what I am starting with

[SOLVED] max height expressed with v, theta, and g Homework Statement what is the max height of a projectile with velocity v at an angle theta using the conservation of energy? express in terms of v, theta, and g Homework Equations 1/2*m*v^2=mgh The Attempt at a Solution i...