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Max height expressed with v, theta, and g

  1. Feb 27, 2008 #1
    [SOLVED] max height expressed with v, theta, and g

    1. The problem statement, all variables and given/known data

    what is the max height of a projectile with velocity v at an angle theta using the conservation of energy? express in terms of v, theta, and g

    2. Relevant equations


    3. The attempt at a solution

    i tried and got (v^2*sin(theta))/2g (wrong)
  2. jcsd
  3. Feb 27, 2008 #2
    You've got the right idea. In fact I think you're close. Actually type out your work and show us, see if you spot the mistake
  4. Feb 27, 2008 #3
    ((1/2)m(v^2)*sin(theta))=mgh...then ((1/2)m(v^2)*sin(theta))/mg=mgh/mg...then the m cancels leaving me with (v^2*sin(theta))/2g=h
  5. Feb 27, 2008 #4
    is my issue the placement of sin(theta) in the equation before i solve for h?
  6. Feb 27, 2008 #5
    wow! what a tedious mistake....it was the placement of the exponent and parenthesis that was wrong...

  7. Feb 27, 2008 #6
    Well my issue was you start here


    It's the VERTICAL velocity you care about, it's 1/2*m*Vy^2=mgh

    Vy=Vsin(theta) so you get 1/2*m*V^2sin^2(theta)
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