Recent content by ultra100

What about when the numerator and denominator both go to 0, so you get 0/0? I tried plugging in small numbers like 0.1 and 0.01 for x and y and i get 3/sqrt(5) as the answer, but my book says the limit does not exist for this equation Is there a way to do L'Hospitals on multivariable limits?

How do I go about finding the limit of a multivariable function? Example: limit as (x,y) approach (0,0) of: (x + 2y) / sqrt (x^2 + 4(y^2)) Do I need to use partial derivatives?

Thanks! This helps a lot

what equations are you using to get y = to +/- 1?

Homework Statement Find the product of the maximum and minimum values of the function f(x, y) = xy on the ellipse (x^2)(1/9) + y^2 = 2 The Attempt at a Solution I tried soving using lagrange multiplier and got: fx = y - (2/9)(x*lambda) fy = x - 2y*lambda flambda = (x^2)(1/9) +...

o wow! that works out... thank's a lot for all your help :smile:

The solution formula is Y = Yc + Yp Yc = (C1 e^-2x) + (C2 e^2x) + (C3 xe^-2x) <--- since this C3 matches 6xe^2x, the rule is that it has to increased in power and it becomes 6x^2e^2x the formula to find Yp when the polynomial in front of e^2x is of 2nd power is (Ax^2 + Bx + C) e^2x y...

since 6xe^(2x) matches the general term C3xe^(2x), the 6x has to be raised in power to 6x^2; in that case the equation is (Ax^2 + Bx +C)e^(2x)... but when I try to take all 3 derivatives of this function and then substituting them back into the y''' - 2y'' - 4y' + 8y equation, it doesn't match...

Solve this equation by superposition approach (undetermined coefficients); pg. 154 in Zill, according to the formula Y = Yc + Yp ---------------------------------------------------- y''' -2y'' -4y' +8y = 6xe^(2x) I got: Yc = C1 e^(-2x) + C2 e^(2x) + C3 xe^(2x) for the complementary...