Finding Limit of Multivariable Function

Click For Summary
SUMMARY

The discussion focuses on finding the limit of a multivariable function, specifically the limit as (x,y) approaches (0,0) for the function (x + 2y) / sqrt(x^2 + 4(y^2)). It is established that partial derivatives are not necessary for evaluating multivariable limits. Instead, users should evaluate the limit by substituting different paths, such as x = 0, y = 0, and x = y. If the results from these paths do not match, the limit does not exist. The use of L'Hôpital's rule is also clarified as inapplicable for multivariable limits.

PREREQUISITES
  • Understanding of multivariable calculus concepts
  • Familiarity with limits in single-variable calculus
  • Knowledge of substitution methods in calculus
  • Basic algebra skills for manipulating expressions
NEXT STEPS
  • Research methods for evaluating limits of multivariable functions
  • Study the epsilon-delta definition of limits in multivariable calculus
  • Explore path-dependent limits and their implications
  • Learn about continuity and differentiability in multivariable functions
USEFUL FOR

Students and educators in calculus, mathematicians, and anyone seeking to deepen their understanding of multivariable limits and their evaluation techniques.

ultra100
Messages
9
Reaction score
0
How do I go about finding the limit of a multivariable function? Example:

limit as (x,y) approach (0,0) of:

(x + 2y) / sqrt (x^2 + 4(y^2))



Do I need to use partial derivatives?
 
Physics news on Phys.org
No. When dealing with multivariable limits you do not find their partial derivatives. Instead, you take a few instances and compare the results to each other. Such as x = 0, y = 0, x= y. If none of them match, then you can be certain that the limit does not exist.
 
jheld said:
No. When dealing with multivariable limits you do not find their partial derivatives. Instead, you take a few instances and compare the results to each other. Such as x = 0, y = 0, x= y. If none of them match, then you can be certain that the limit does not exist.


What about when the numerator and denominator both go to 0, so you get 0/0?

I tried plugging in small numbers like 0.1 and 0.01 for x and y and i get 3/sqrt(5) as the answer, but my book says the limit does not exist for this equation

Is there a way to do L'Hospitals on multivariable limits?
 
No, unfortunately you can't use L'Hospitals for mutlivars. When both num and denom go to 0, that means that you need to substitute in y and x in different ways, like x = 0 in one case, and then y = 0 in another case, and then x = y in another. don't do them at the same time. don't plug in actual numbers (other than 0), only stuff like I noted above.
 

Similar threads

Replies
7
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
6
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 27 ·
Replies
27
Views
2K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K