according to circuit
In Left Loop Current is I1 and Right Loop is I2
Now Loop Left
10-8I1-3I1-I2=0
which becomes
10-8I1-3I1+3I2=0
11I1-3I2-10=0 ------------eq 1
Now Loop Right
15-6I2-3I2-I1=0
15-6I2-3I2+3I1=0
3I1-9I2+15=0
I1-3I2+5=0 ---------------eq 2
Deduct eq 2 from eq 1...
i was thinking that evaluation is like polar form i don't know how to resolve this, i know nothing about
r^{i\theta} = x + iy
please tell me what i have to do,
its polar representation is Z = r[Cos(thita) + iSin(thita)]
is it is Evaluation
i want to know what actually i have to do in evaluation
Thanks for your help :)
Hi PFs
i want to know how to evaluate the complex number, and what are the meaning of the evaluating a complex number
Let Z be the complex number, Z = (3-4i)^5 what i have to do, just give me hint
hi PF
1. (2+2i) First Quadrant
2. (-2+2i) Second Quadrant
3. (-2-2i) Third Quadrant
4. (2-2i) Fourth Quadrant
consider (2+1i) then Tan^-1(2/2) which will be 45 degree
if we consider (-2+2i) then it will be -45 degree but angle will not -45 degree actually we get answer by adding or...
ohh i really got point i have got that i have have to substitute a^2 - x^2 with (u or any alphabet) and then i have to apply limit am i right Thanks tiny :)