How to integrate something that keeps on repeating

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Homework Help Overview

The discussion revolves around the integral of the expression e^t (1 + 3sin(t)). Participants are exploring integration techniques, particularly integration by parts, in the context of calculus.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use integration by parts but encounters difficulties, particularly with the relationship between the left-hand side and right-hand side of the equation. Some participants question the clarity of the integral's expression, suggesting alternative interpretations of the notation.

Discussion Status

Some guidance has been offered regarding splitting the integral into simpler components, with one participant suggesting a method involving integration by parts. However, there is no explicit consensus on the correct interpretation of the integral, and multiple approaches are being explored.

Contextual Notes

There is a mention of potential confusion regarding the notation used in the integral, which may affect the understanding of the problem. The original poster expresses uncertainty about the validity of their approach and the implications of the terms involved.

dwilmer
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Homework Statement


What is integral of e^t (1+3sint)?
I tried integ by parts but its not working
Im familiar with the technique where you end up with two idental integrals on either side, then you add one side to the other, and divide by 2.
This isn't working though. Mainly because the RHS will never be same as term on LHS, because the 1 either cancels or else becomes a t, at the first integration or differentiation.

Please help.


Homework Equations





The Attempt at a Solution

 
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You mean

e^t (1+3\sin(t))

or

e^{t (1+3\sin(t))}

not that I will know in either case, just it is not clear to me what the question is.
 
dwilmer said:

Homework Statement


What is integral of e^t (1+3sint)?
I tried integ by parts but its not working
Im familiar with the technique where you end up with two idental integrals on either side, then you add one side to the other, and divide by 2.
This isn't working though. Mainly because the RHS will never be same as term on LHS, because the 1 either cancels or else becomes a t, at the first integration or differentiation.

Please help.
I suspect you mean \int e^t (1+ 3sin(t)dt because Borek's suggested \int e^{t(1+ 3sin(t)}dt, while plausible from what you wrote, is intractible.

First, split the integral up: \int e^t dt+ 3\int e^t sin(t)dt. The first is easy and the second can be done by the technique you mention. One integration by parts gives a term of \int e^t cos(t)dt and a second gives \int e^t sin(t)[/tex] again.<br /> <br /> <br /> <blockquote data-attributes="" data-quote="" data-source="" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> <h2>Homework Equations</h2><br /> <br /> <br /> <br /> <h2>The Attempt at a Solution</h2> </div> </div> </blockquote>
 
thanks Halls
 

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