How to integrate something that keeps on repeating

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SUMMARY

The integral of e^t(1 + 3sin(t)) can be solved by separating it into two parts: ∫e^t dt and 3∫e^t sin(t) dt. The first integral is straightforward, while the second requires integration by parts. This method leads to a recursive relationship where the integral of e^t sin(t) reappears, allowing for a solution through algebraic manipulation. The discussion clarifies the confusion around the notation and confirms the correct interpretation of the integral.

PREREQUISITES
  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with exponential functions and trigonometric functions.
  • Knowledge of recursive relationships in integrals.
  • Basic calculus concepts, particularly integral calculus.
NEXT STEPS
  • Study the integration by parts technique in detail.
  • Learn about solving integrals involving products of exponential and trigonometric functions.
  • Explore the method of reduction formulas for integrals.
  • Practice solving similar integrals to reinforce understanding.
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Students and educators in calculus, particularly those tackling integration problems involving exponential and trigonometric functions. This discussion is beneficial for anyone looking to enhance their skills in solving complex integrals.

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Homework Statement


What is integral of e^t (1+3sint)?
I tried integ by parts but its not working
Im familiar with the technique where you end up with two idental integrals on either side, then you add one side to the other, and divide by 2.
This isn't working though. Mainly because the RHS will never be same as term on LHS, because the 1 either cancels or else becomes a t, at the first integration or differentiation.

Please help.


Homework Equations





The Attempt at a Solution

 
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You mean

e^t (1+3\sin(t))

or

e^{t (1+3\sin(t))}

not that I will know in either case, just it is not clear to me what the question is.
 
dwilmer said:

Homework Statement


What is integral of e^t (1+3sint)?
I tried integ by parts but its not working
Im familiar with the technique where you end up with two idental integrals on either side, then you add one side to the other, and divide by 2.
This isn't working though. Mainly because the RHS will never be same as term on LHS, because the 1 either cancels or else becomes a t, at the first integration or differentiation.

Please help.
I suspect you mean \int e^t (1+ 3sin(t)dt because Borek's suggested \int e^{t(1+ 3sin(t)}dt, while plausible from what you wrote, is intractible.

First, split the integral up: \int e^t dt+ 3\int e^t sin(t)dt. The first is easy and the second can be done by the technique you mention. One integration by parts gives a term of \int e^t cos(t)dt and a second gives \int e^t sin(t)[/tex] again.<br /> <br /> <br /> <blockquote data-attributes="" data-quote="" data-source="" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> <h2>Homework Equations</h2><br /> <br /> <br /> <br /> <h2>The Attempt at a Solution</h2> </div> </div> </blockquote>
 
thanks Halls
 

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