Recent content by Vriska

I dunno, say for example that n(n+1)(n+2)(n+3) leads to a number like 9 ie 3*3 . this cannot be written as a fourth power in form (n+a)^4, can it ?

Ah hello, thanks for the response Can you tell me why you put it as (n+a)^4 ? surely if it's a perfect square it should be of form k^2 where k = n + a. we can't say if k will remain an integer if another root is taken to make it to the fourth power .

Thanks btw would you know why I've got no response yet? Is what I've written badly wrong or am I just not clear enough here ?

Agh, I meant product !

Homework Statement n(n+1)(n+2)(n+3) cannot be a square Homework Equations Uniqueness of prime factors for a given number The Attempt at a Solution I'm not sure but I think I've proved a stronger case for how product of consecutive numbers cannot be squares. I don't know whether it is right...

okay real depth at supper surface of upper fluid is d + d*sqrt(2)/n so sqrt 2 = d +d*sqrt(2)/apparent depth. ad =d(n+sqrt2)/n*sqrt2. thanks! BTW, would you happen to know if the method used in the book make sense?

okay mathematically : change in depth due to medium 2 = d- sqrt(2)d/n, due to medium 1 = d - d/sqrt(2), total change in depth is 2d - sqrt(2)d/n - d/sqrt(2) this is subtracted from total depth to get apparent depth . = sqrt(2)d/n +d/sqrt 2. wrong answer, right?

I just under the upper fluid? Then thered be no refraction right?

if I were at the bottom of interface at distance d, the apparent depth would be d*##\sqrt 2## /n. my guess was I'd add this to the ##\frac{d} {\sqrt 2}##, that's wrong apparently

Homework Statement both filled to height h in the vessel of length 2h. one has refractive index root 2 and the bottom fluid has refractive index n. find the apparent depth of vessel. Homework Equations n = real depth/apparent depth The Attempt at a Solution what these guys have done ...

they drew a v versus I plot, with Voltage on the y-axis and drew a line on the plot with its y coordinate of its end being v_i - v_c and the x coordinate being v_r. The angle between the line and the x-axis was the phase angle. not quite sure what they're doing here :|

aright the power wave will look like road bumps. frequency will be half of that of voltage and current waves p =v^2 /r sin^2(wt). so max power = v^2/r.. how do I go from here?

Homework Statement apparently your effective power is V_maxI_max * cos(x) where x is the phase angle. So I must consider only real power Homework Equations power = VI current = I sin(wt) The Attempt at a Solution Let impedence be = e^ix . I'll write current as Ie^i(wt) consideronly the real...

woh thanks, I didn't see the response but I was thinking of this problem again so I can back to see if OP got answered. so they mean something like (voltage on thing being driven) /(voltage that should actually be there (eg 220)? ,if that were the case you could find the load? What about...

Homework Statement The capacitor (of thickness d) is disconnected from a potential source of V and a dielectric of thickness t is inserted and it has relative permitivity Er. Find the new potential between the plates Homework Equations [/B] This is the answer : Vf = V/d(d - t + t/Er) The...