Recent content by walleye3

64000 N/ 0.00074m2 = 86486486.49 Pa > 86486.48649 kPa F/S Ultimate stress/Allowable Stress = 550 MPa/86486.48649 > 550000kPa /86486.48649= 6.359

okay thank you... i see my mistake

1 cm = 0.01 m ...

Load/Area= 64000N/0.074m= 864864.8649 Pa > 864.864 kPa F/S = Ultimate stress/ Allowable Stress = 550 MPa/ 864.864 kPa > 550000 kPa/ 864.864kPa = 635.938 is (635.938 ) my answer ? (factor of safety) ??

oh , i need metres squared

well i went load/ area > 64000N/7.4cm squared = 8648.65 Pa 550 MPa = 550000kPa/8.648kPa (ultimate stress/allowable stress) =63594.11 63.59 as my answer is that correct ? if not please...

Load divided by area ...right ? , when it gives me cross sectional area do I need to do anything mathematically with it or do I plug that number in ?

Homework Statement What is the factor of safety of a steel hanger having an ultimate strength of 550.00 MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.400cm squared Homework Equations The Attempt at a Solution i understand the...